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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Rigid Body Dynamics
Rotational-Motion
Duration: 5.17 Min
 
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Moment-of-Inertia
Duration: 7.49 Min
 
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Moment-of-Inertia-of-a-Ring
Duration: 1.31 Min
 
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Moment-of-Inertia-of-a-Disc
Duration: 3.50 Min
 
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Moment-of-Inertia-of-a-Hollow-Sphere
Duration: 5.16 Min
 
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Moment-of-Inertia-of-a-Solid-Sphere
Duration: 3.36 Min
 
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Moment-of-Inertia-of-a-Hollow-Cone
Duration: 4.41 Min
 
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Moment-of-Inertia-of-a-Solid-Cone
Duration: 4.13 Min
 
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Moment-of-Inertia-of-a-Thin-Rod
Duration: 4.31 Min
 
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Axes-Theorem-Perpendicular-Axes-Theorem
Duration: 16.34 Min
 
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Axes-Theorem-Parallel-Axes-Theorem
Duration: 14.42 Min
 
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Radius-of-Gyration
Duration: 4.05 Min
 
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Solved-Example-1
Module - 13 Solved Example-1
Duration: 1.55 Min
 
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Solved-Example-2
Module - 14 Solved Example-2
Duration: 3.29 Min
 
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Solved-Example-3
Module - 15 Solved Example-3
Duration: 4.31 Min
 
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Solved-Example-4
Module - 16 Solved Example-4
Duration: 2.15 Min
 
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Newtons-Second-Law-in-Rotational-Motion
Duration: 9.58 Min
 
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Solved-Example-5
Module - 18 Solved Example-5
Duration: 2.47 Min
 
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Solved-Example-6
Module - 19 Solved Example-6
Duration: 5.07 Min
 
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Solved-Example-7
Module - 20 Solved Example-7
Duration: 4.44 Min
 
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Solved-Example-8
Module - 21 Solved Example-8
Duration: 2.21 Min
 
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Solved-Example-9
Module - 22 Solved Example-9
Duration: 3.28 Min
 
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Angular-Momentum
Module - 23 Angular Momentum
Duration: 17.59 Min
 
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Conservation-of-Angular-Momentum
Duration: 7.25 Min
 
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Solved-Example-10
Duration: 2.37 Min
 
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Solved-Example-11
Duration: 2.53 Min
 
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Solved-Example-12
Duration: 3.25 Min
 
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Solved-Example-13
Duration: 2.35 Min
 
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Concept-of-Angular-Impulse
Duration: 10.39 Min
 
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Solved-Example14
Module - 32 Solved Example14
Duration: 7.32 Min
 
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Solved-Example15
Module - 33 Solved Example15
Duration: 4.03 Min
 
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Solved-Example16
Module - 34 Solved Example16
Duration: 4.49 Min
 
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Solved-Example17
Module - 35 Solved Example17
Duration: 4.48 Min
 
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Solved-Example18
Module - 36 Solved Example18
Duration: 4.40 Min
 
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Analysis-of-Rolling-with-Sliding
Duration: 11.41 Min
 
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Solved-Example19
Module - 38 Solved Example19
Duration: 2.24 Min
 
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Solved-Example20
Module - 39 Solved Example20
Duration: 4.45 Min
 
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Work-and-Power-in-Rotational-Motion
Duration: 7.53 Min
 
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Solved-Example-21
Duration: 3.36 Min
 
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Solved-Example-22
Duration: 4.51 Min
 
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  1.  
    2. Respected Sir, I have a doubt that you have considered static friction in pure rolling as you have mentioned in your previous slide that we are suppose to account friction whenever there is an Fext.My doubt is that which external force is accounted here is force F on whole system?
    2 years ago by Umang Kumar

    Post your answer here

  2.  
    3. Sir for the rotational part too the equation should be fR=((MR^2)(a2-a1))/2r because a1 is acceleration of cylinder w.r.t the plank not w.r.t the ground.
    6 years ago by Bala Rajput

    Post your answer here

  3.  
    4. sir in this question i think the first equation should be equal to F-f=5ma as the force is being applied on plank of mass 4m but sphere is also present on the top of it which has a mass m.Sir please solve this query..
    9 years ago by Kanav
    Ans 1 ->
    sir wrote this equation by considering the plank as a system....by drawing the free body daigram of the plank and the cylinder u ll be able to get ur answer...
    8 years ago by Khushboo Jain
    Ans 2 ->
    sir it is a cylinder not a sphere!
    8 years ago by Pranav Satheesh
    Ans 3 ->
    Sir for the rotational equation shouldn't acceleration of cylinder be a2-a1. Thus the equation should be- fR=(MR^2)/2*(a2-a1)/r
    7 years ago by Akshunn Trivedi

    Post your answer here

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